Did you know?

Trying to factor as a Difference of Squares : 1.1 Factoring: mc50-jpg Theory : A difference of two perfect squares, A2- B2 can be factored into (A+B) • (A-B) Proof : (A+B) • (A-B) =A2 - AB+BA- B2= A2- AB + AB - B2 = A2 - B2 Note : AB = BA is the commutative property of multiplication. Note : - AB + AB equals zero and is therefore eliminated ...Expert-Verified Answer. The correct solution is x = 12/5, and the other options are not valid solutions. To solve the equation √ (x^2+49) = x+5, we can square both sides to eliminate the square root: x^2 + 49 = (x+5)^2. Expanding and simplifying: x^2 + 49 = x^2 + 10x + 25. Subtracting x^2 from both sides: 49 = 10x + 25.The potential solutions are x = √26 and x = -√26. Step-by-step explanation: The given expression is ln(x² - 25) = 0. It can be rewritten as [Since base of a natural logarithm is considered as e] Since in a logarithmic function if . Then . Now we further solve the expression to get the possible roots. x = ±√26

Step-by-step explanation: We have been given an equation: We can see that the graphical method gives the solution by intersection of two graphs. So, one graph is of parabola open upwards. And the right hand side is the straight line. Option 1 and 2 are discarded being open downwards. And Option 3rd is correct.The solution to the equation is x = -8 or x = -1. To find the solution of the equation √(1-3x) = x+3, we can use algebraic techniques to isolate the variable x. First, let's square both sides of the equation to eliminate the square root: Simplifying, we get: Next, let's gather all the terms on one side of the equation: Simplifying further, we ...When it comes to vehicle repairs, finding cost-effective solutions is always a top priority for car owners. One area where significant savings can be found is in the replacement of...The density of the NaCl solution is 1.0 g solution/mL solution. star. 4/5. heart. 5. For which pair of functions is the exponential consistently growing at a faster rate than the quadratic over the interval mc015-1. Jpg? mc015-2. Jpg mc015-3. Jpg mc015-4. Jpg mc015-5. Jpg. heart. 8. Load more.Answers archive. Click here to see ALL problems on Trigonometry-basics. Question 1100087: Which property is demonstrated below? mc015-1.jpg. Found 2 solutions by Edwin McCravy, richwmiller: Answer by Edwin McCravy (19705) ( Show Source ): You can put this solution on YOUR website!

Our expert help has broken down your problem into an easy-to-learn solution you can count on. ... Find the equation of the sphere whose center is mc013-1.jpg and radius is mc013 …Mar 1, 2022 · The potential solutions of are 2 and -8. Properties of Logarithms. From the properties of logarithms, you can rewrite logarithmic expressions. The main properties are: Product Rule for Logarithms - Quotient Rule for Logarithms - Power Rule for Logarithms - The exercise asks the potential solutions for . ….

Reader Q&A - also see RECOMMENDED ARTICLES & FAQs. What are the potential solutions of mc015-1.jpg. Possible cause: Not clear what are the potential solutions of mc015-1.jpg.

Your solution’s ready to go! Our expert help has broken down your problem into an easy-to-learn solution you can count on. See Answer See Answer See Answer done loading. Question: Question 15 (1 point) What is the correct equilibrium constant expression for the following reaction? 2NC13(g) + 3Cl2(g) 0 N2(g) O [NZ][C1,13 [NC13] Ke = [NC1,] [N ...Jan 4, 2022 · Identify the reference angle es001-1. Jpg for each given angle, es001-2. Jpg. Es001-3. Jpg degrees. Es002-1. Jpg degrees. Es003-1. Jpg degrees.

Answer : The pH of a solution is, 9.903. Explanation : Given, Concentration of hydrogen ion =. pH : It is defined as the negative logarithm of hydrogen ion concentration. Formula used : Now put the value of hydrogen ion concentration in this formula, we get the pH of a solution. Therefore, the pH of a solution is, 9.903. arrow right.Final answer: The equations 2x² + 6x + 9, x² + 3x + 12, and x² + 3x + 3 all have negative discriminants, indicating that they have complex solutions as required by the student question.. Explanation: The student is asking which of the given equations has complex solutions.. For a quadratic equation of the form ax² + bx + c = 0, the discriminant (b² - 4ac) determines the nature of the roots.The equation Mg (s) mc015-1.jpg 2HCl (aq) mc015-2.jpg MgClmc015-3.jpg (aq) mc015-4.jpg Hmc015-5.jpg (g) is an example of which type of reaction?

mythic egg adopt me Answer. The solution to the equation is x = -8 or x = -1. To find the solution of the equation √ (1-3x) = x+3, we can use algebraic techniques to isolate the variable x. First, let's square both sides of the equation to eliminate the square root: Simplifying, we get: time card viewer upserskaiser permanente panola pharmacy number In today’s digital age, ensuring the security and privacy of student data is of utmost importance. Educational institutions are constantly seeking innovative solutions to protect s...x. y. z. ␣. Solution - Simplification or other simple results. m c 5 − j p g. mc^5-jpg. Other Ways to Solve. Simplification or other simple results. merch bnkcd nsd discount Write a standard-form quadratic equation with –4 and 3/2 as solutions. a 2x2 + 5x – 12 = 0 b 2x2 – 5x – 12 = 0 c 3x2 + 10x – 8 = 0 d 3x2 – 10x – 8 = 0 e none of the above heart 1To find the potential solutions of the equation log_4(x) + log_4(x+6) = 2, combine the logs, convert to exponential form, and solve the resulting quadratic equation. Explanation: The potential solutions of the equation log4(x) + log4(x+6) = 2 can be found by using properties of logarithms. eugene craigslist cars and trucksbrownsville tx radarmountain goat nyt crossword clue 1. The Mole Crossword Puzzle Answer Key. An Overview . The Mole Crossword Puzzle is a challenging and rewarding crossword puzzle that has captivated puzzle enthusiasts for decades. Created by Thomas Joseph “Will” Shortz, the puzzle is known for its clever clues and intricate grid design. ... What Are The Potential … brian of rock crossword clue Mar 28, 2019 · x 8 is x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 and we want to take out groups of three (for cubed root) x-variables to get (x 1 x 1 x 1)(x 1 x 1 x 1)x 1 x 1. Remember: x 1 x 1 x 1 = x 3. We have TWO groups (x 1 x 1 x 1) we can take out therefore on the outside we write x 2 and under the radical we have x 1 x 1 which is x 2. hay dude critter rescuemarshall county gis indianawinhr nissan Solution - Simplification or other simple results. m c 13 − j p g. mc^13-jpg. Other Ways to Solve. Simplification or other simple results.